Question 452359

{{{3x^2-5x-2=0}}}...use quadratic formula


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} ........{{{a=3}}}, {{{b=-5}}}, and {{{c=-2}}}


{{{x = (-(-5) +- sqrt( (-5)^2-4*3*(-2) ))/(2*3) }}}


{{{x = (5 +- sqrt( 25+24 ))/6 }}}


{{{x = (5 +- sqrt( 49 ))/6 }}}


{{{x = (5 +- 7)/6 }}}


solutions are:


{{{x = (5 + 7)/6 }}}


{{{x = 12/6 }}}


{{{x = 2 }}}


or


{{{x = (5 - 7)/6 }}}


{{{x = -2/6 }}}


{{{x = -1/3 }}}