Question 452318
First this is to understand Quadratic is all bout the finding the zero's.

so x^3 - 8 = 0
x^3 = 8
x = 2
We can use The Difference of Two Cubes Formula to solve this.

The formula says a^3 - b^3. If we factor (a - b) out we will get (a - b)(a^2 + ab + b^2).

So lets put your info in the formula. 

let a = x and b = 2

x^3 - 2^3


Now factor x-2 out and we are left with (x-2)(x^2 + 2x + 2^2)

So x^3 - 8 = x^3 - 2^3 = (x-2)(x^2 + 2x + 2^2)



If you need more help, just ask!