Question 452348
Trains A and B are traveling the same direction on parallel lines.
 Train A is traveling 100 mph and train B is traveling 120 mph.
 Train A passes the station at 5:25 am and train B passes station at 5:37 am, what time will train B catch up with train A?
:
From the given information, we know that Train B is 12 min behind A at at 5:25 pm
therefore Train B is:
{{{12/60}}} * 120 = 24 miles behind Train A at that time.
:
Let t = time required for Train B to catch Train A
:
Write a distance equation; dist = speed * time
:
Train B dist = Train A dist + 24 mi
120t = 100t + 24
120t - 100t = 24
20t = 24
t = {{{24/20}}}
t = 1.2 hrs for B to catch A 
:
Convert 1.2 hrs to hrs and minutes: 1 + .2(60) = 1 hr 12 min
:
Find the time from 5:25 pm:
5:25 + 1:12 = 6:37 pm, Train B catches Train A