Question 452265
First we have to find the slope of a line by using the two given points.
  x1 y1      x2  y2
(-3,-8) and (-9,-5)


m = y2-y1/x2-x1

-5-(-8)/-9 - (-3)  {substitute y2,y1,and x2,x1}
-5+8/-9+3 
3/-6  {simplify}
-1/2

so m = -1/2

Now we will use the point slope form to find the equation of a line.

You can use either one of the points already given. I will use the first point. (-3,-8).


y-y1=m(x-x1) {point slope form}
y-(-8) = (-1/2)(x-(-3))  {substitute m,x1,and y1}
y + 8 = -1/2x - 3/2  {subtract 8 from both sides}
y = -1/2x - 3/2 -8  {simplify -3/2-8}
y = -1/2x - 9/2

You can check my take the point slope form and using the other point (-9,-5). You will still end up with the same answer.

So y = -1/2x -9/2 is the equation of the line with a slope of -1/2x that passes through the points (-3,-8) and (-9,-5).

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