Question 452133
What is the equation for the line containing given point and parallel to the given line: (5,-4); 
4x-3y=8
put in the slope/intercept form
-3y = -4x + 8
y has to be positive, multiply both sides by -1
3y = 4x - 8
y has to have coefficient of 1, divide both sides by 3
y = {{{4/3}}}x - {{{8/3}}}
Parallel lines have the same slope
Use the point/slope form to find the parallel line y - y1 = m(x-x1)
x1=5, y1=-4, m= {{{4/3}}}
y - (-4) = {{{4/3}}}(x - 5)
y + 4 = {{{4/3}}}x - {{{20/3}}} 
y = {{{4/3}}}x - {{{20/3}}} - 4
y = {{{4/3}}}x - {{{20/3}}} - {{{12/3}}}
y = {{{4/3}}}x - {{{32/3}}}