<PRE><B>Question 452173</B>
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ -\ 18\ +\ x\ =\ 180]


Solve for *[tex \Large x] and then calculate *[tex \Large 2x\ -\ 18].  


Check your work.  Calculate *[tex \Large 180\ -\ x] which should be the same as *[tex \Large 2x\ -\ 18]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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