Question 452174
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You should have posed the question:


If the slope of a line is 1/2 and the <i>y-coordinate of</i> the y-intercept is -2, what is the linear equation in the slope-intercept form?   That is because a *[tex \Large y]-intercept is a point that must be represented by an ordered pair (in *[tex \Large \mathbb{R}^2]), and is typically rendered as *[tex \Large (0,\,b)].


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ mx\ +\ b]


is the slope-intercept form of a line where the slope is *[tex \Large m] and the *[tex \Large y]-coordinate of the *[tex \Large y]-intercept is *[tex \Large b].


Just substitute whatever values you like for *[tex \Large m] and *[tex \Large b].



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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