Question 452121
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 9x\ +\ 8y\ =\ -21]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -6x\ +\ y\ =\ 33]


Note that the second equation already has one of the variables with a coefficient of 1, namely the *[tex \Large y].  So the simplest strategy would be to solve the second equation for *[tex \Large y] in terms of everything else by adding *[tex \Large 6x] to both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 6x\ +\ 33]


Now that you have an expression in *[tex \Large x] that is equal to *[tex \Large y] you can substitute back into the first equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 9x\ +\ 8(6x\ +\ 33)\ =\ -21]


Now you have a single equation in a single variable that can be solved by ordinary means.  Solve for *[tex \Large x].  Then substitute the calculated value of *[tex \LARGE x] back into the second given equation and solve for the value of *[tex \Large y].  Your ordered pair will be your two calculated values in order *[tex \Large \left(x,\,y\right)].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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