Question 452115
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I did this for you yesterday, but here it is again.


Use the factorization of the difference of two cubes:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^3\ -\ b^3\ =\ (a\ -\ b)\left(a^2\ +\ ab\ +\ b^2\right)]


And recall that *[tex \Large 2^3\ =\ 8].


For future reference, you can remember the sum and difference of two cubes thusly:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^3\ \pm\ b^3\ =\ (a\ \pm\ b)\left(a^2\ \mp\ ab\ +\ b^2\right)]


Use the mnemonic "San Diego Padres" to remember "Same sign, Different sign, Plus sign" to help you know which signs to put into the right hand side of the equation.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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