Question 452078
State the range of y=-e^x+1, and find the asymptote of itd graph?
For large x, y -> -{{{infinity}}}
For large negative x, y -> 1
So the range is (-{{{infinity}}},1)
The asymptote is y = 1.
The graph is below:
{{{graph(300,300,-10,10,-20,4,-e^x+1)}}}