Question 452078
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That depends.


Do you mean:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ -e^x\ +\ 1]


which has a range of


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \{y\,|\,-\infty\ <\ y\ <\ 1,\,y\ \in\ \mathbb{R}\}]


and is asymptotic to


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 1]


or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ -e^{x\,+\,1}]


which has a range of


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \{y\,|\,-\infty\ <\ y\ <\ 0,\,y\ \in\ \mathbb{R}\}]


and is asymptotic to


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 0\ \ ], i.e. the *[tex \LARGE y]-axis.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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