Question 451852
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The diagonal of a rectangle is the hypotenuse of a right triangle, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ w^2\ +\ (w\ +\ 3)^2\ =\ 15^2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2w^2\ +\ 6w\ +\ 9\ =\ 225]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2w^2\ +\ 6w\ -\ 216\ =\ 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ w^2\ +\ 3w\ -\ 108\ =\ 0]


Just solve for *[tex \Large w], discard the extraneous negative root, and then calculate *[tex \Large w\ +\ 3]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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