Question 451850
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ lw]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ lw\ =\ 26]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ l\ =\ \frac{26}{w}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ 2l\ +\ 2w]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2l\ +\ 2w\ =\ 30]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2\left(\frac{26}{w}\right)\ +\ 2w\ =\ 30]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{26}{w}\ +\ w\ -\ 15\ =\ 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ w^2\ -\ 15w\ +\ 26\ =\ 0]


Just solve for *[tex \Large w], then substitute the value of *[tex \Large w] into *[tex \Large l\ =\ \frac{26}{w}] and solve for *[tex \Large l]




John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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