Question 451739
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Hi
Standard Form of an Equation of a Circle is {{{(x-h)^2 + (y-k)^2 = r^2}}}
where Pt(h,k) is the center and r is the radius
center (-1,5)
{{{(x+1)^2 + (y-5)^2 = r^2}}}

(-1,5)
(23,-2) D = {{{sqrt ((x[1]-x[2])^2+(y[1]-y[2])^2))}}} = 
        D = {{{sqrt( (-24)^2+(7)^2)}}} = {{{sqrt (625)}}} = 25
{{{(x+1)^2 + (y-5)^2 = 625}}}