Question 451698
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Hi, 
{{{(2^1w^1y^(-3))^4 / 4y^(-2)=  2^4w^4y^(-12)/ 4y^(-2)= 16w^4/4y^10= 4w^4/y^10}}}
Note: {{{y^(-12)/y^(-2)= 1/y^(12-2)= 1/y^10}}}