Question 451137
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Hi
*[tex \LARGE\ \ log_b(x^n) = nlog_bx  ]
 log(10^4x+3)= (4x+3)log 10 = 7
 
*[tex \LARGE \ \ \ \ \  \ \ \ b^y = x \ \ \ \ \ \Rightarrow\ \ \ \ \ \ \ y = \log_b(x) ]
  log 10 = 1  as 10^1 = 10
   4x+3 = 7
     4x = 4
      x = 1