Question 451462
5) 
Let c=cost of the car.
.06(6000-c)/3 + 2*.04(6000-c)/3  = 140
.06(6000-c)+.08(6000-c)=420 multiply each side by 3.
360-.06c+480-.08c=420
-.14c=-420
c=$3000.
.
Ed