Question 46846
{{{f^1 (x)}}} is just {{{f(x)}}}.
{{{f(x)=3-(x-5)^2}}}
{{{x<=5}}}
The maximum value will occur when nothing is subtracted from the 3 in f(x), i.e. when x=5. 
{{{f(5)=3}}}
All other values of x will give f(x)<3, and there is no lower limit to the value of f(x), it will be negative infinity when x=-infinity.
I have dr4awn the graph up to x=5 below.
{{{ graph( 300, 200, 0, 5, -22, 4, 3-(x-5)^2) }}} 
I hope this helps,
Adam
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