Question 451227
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Hi,
<img src="http://upload.wikimedia.org/wikipedia/commons/thumb/d/da/PerimeterRectangle.svg/200px-PerimeterRectangle.svg.png">

The length of a rectangle is 5yds  longer than its width. 
Let x and (x+5) represent the width and length respectively
  2x + 2(x+5yd) = 30yds
   4x =  20yds
    x = 5yd, the width the length is 10yd
Area(rectangle) = w*l = 5yd*10yd = 50yd^2