Question 451172
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Hi,
Suppose you are asked to pick '3 numbers' from 1 to 20 to win a prize
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case p(picking the winning number)= 1/20 and q = 19/20
nCx = {{{n!/(x!(n-x)!)}}}
 P(picking the winning number) = 3C1(.05)^1 (.95)^2 = .1354