Question 451144
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
10t^2 - 8t = 0  2t(5t-4)=0    t = 0,.8   (2-real solutions)
x^2+2x+1=4 
x^2+2x-3=0   (x+3)(x-1)= 0    x = -3,1
x^2+13/2x=13
(x+13/4)^2 = 13 + 169/16 = 208/16 + 16*/169 = 377/16
 x + 13/4 = ± sqrt(377)/4
    x = -13/4 ± sqrt(377)/4  | x = -13/4 + sqrt(377/4),-13/4 - sqrt(377/4)

(x-5)^2=18
 x-5 = ± sqrt(18)= ± sqrt(9*2)= ± 3sqrt(2)
   x = 5 ± 3sqrt(2) | x = 5+3sqrt(2), 5-3sqrt(2) (exact solutions)
   x = 5 ±  4.243   | x = .757, 9.243   (approximate solutions)

x^2 + 1/2x = 13
 x(+1/4)^2 = 13 + 1/16 = 208/16 + 1/16 = 209/16
    x = -1/4 +sqrt(209)/4, -1/4-sqrt(209)/4