<PRE><B>Question 450731</B>
Note that if the quadratic equation is in the form


*[tex \LARGE ax^2 + bx + c = 0], then


*[tex \LARGE x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}]


Simply equate the coefficients. Here, a = 1, b = -4, and c = -7, because the x^2 coefficient is 1, etc. Then replace them into the quadratic formula to find the two possible values of x.


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