<PRE><B>Question 451024</B>
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Think about how you get the average.  You added up the 6 scores and divided the total by 6.  That means that the total of the 6 scores is 82 times 6.  If you add the 5 scores you know, you can subtract that total from the product 82 times 6 and the difference has to be the unknown score.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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