Question 450971
How much of a 5% acid solution and a 20% acid solution must be mixed in order to obtain 3 gallons of a 10% acid solution? 
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Equations:
Quantity Eq:: f + t = 3 gallons
Acid Eq:::: 0.05f+0.20t == 0.10*3
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Multiply thru 1st equation by 5.
Multiply thru 2nd equation by 100.
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5f + 5t = 5*3
5f +20t = 10*3
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Subtract and solve for "t":
15t = 5*3
t = 1 gallon (amt. of 20% solution needed)
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Solve for "f":
f + t = 3
f + 1 = 3
f = 2 gallons (amt. of 5% soltuion needed)
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Cheers,
Stan H.