Question 46791
To have all real coefficients, any complex root (7-i) must have a corresponding conjugate root, (7+i) in this case.
We Now know all the roots (values of x when g(x)=0:
2, 3, -3, 7-i and 7+i
So:
g(x)=(x-2)(x-3)(x+3)(x-7+i)(x-7-i)

I hope this helps,
Adam
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