Question 450585
"Solve the equation by a method of your choice.
x^2-2x-3=0"


x² - 2x - 3 = 0 
(x - 3)(x + 1) = 0 {factored into two binomials}
x - 3 = 0 or x + 1 = 0 {set each factor equal to 0}
x = 3 or x = -1 {solved each equation for x}
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