Question 450507


Let roots are  z and 1/z . 


product of roots i.e z * 1/z = [ 4b/ (b^2+4)]


solve 1 = 4b/ (b^2+4)

=> b^2 + 4  = 4b 

=> b^2 - 4b +4  = 0

=> (b-2)^2 = 0

so, b = 2