Question 449937
3y=SquareRootOf2(1-2x/x+1)
:
Assume the problem is:
3y = {{{sqrt(2((1-2x)/(x+1)))}}}
Square both sides
(3y)^2 = {{{2((1-2x)/(x+1))}}}
:
9y^2 = {{{2((1-2x)/(x+1))}}}
:
Multiply both sides by (x+1)
9y^2(x+1) = 2(1-2x)
:
9xy^2 + 9y^2 = 2 - 4x
:
9xy^2 + 9y^2 + 4x = 2 
:
9xy^2 + 4x = -9y^2 + 2
;
Factor out x
x(9y^2 + 4) = -9y^2 + 2
:
divide both sides by (9y^2+4)
x = {{{((-9y^2+2))/((9y^2+4))}}}