<PRE><B>Question 449786</B>
Could you please help me to solve this problem? 
A binomial probability distribution has n = 15 trials with the probability of success on each trial is p = .65. Calculate the following. 
a. The mean,&amp;#61549;, of the distribution:: np = 15*0.65
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b. The standard deviation of the distribution:: sqrt(npq) = sqrt(15*0.65*0.35)
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c. The probability of 10 successes:: 15C10(0.65)^10*(0.35)^5
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d. The probability of 10 failures::: 15C10(0.35)^10*(0.65)^5
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e. The probability of at least 14 successes::
Ans: P(14&lt;= x &lt;= 15) P(x = 14) + P(x = 15) = 15C14(0.65)^14*(0.35)+(0.65)^15
= 15*0.0024*(0.35) + 0.0016
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= 0.01416
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Cheers,
Stan H.
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