Question 46716
I have provided an example here. Just plug in your own values and follow my method. I promise it will work
The eqautaion {{{y=-mx+b}}} is the equation of a straight line. {{{m}}} is the gradient of that line, and {{{b}}} is the y-axis intercept. The y-axis intercept is the value of y when x=0. 

Try to remember this equation: {{{(y-y[1])/(y[2]-y[1])=(x-x[1])/(x[2]-x[1])}}} 
where (x1,y1) and (x2,y2) are points on the line. It is an EXTREMELY important equation.
Lets do an example:
(x1,y1)=(1,2)
(x2,y2)=(3,4)
substitute these values into {{{(y-y[1])/(y[2]-y[1])=(x-x[1])/(x[2]-x[1])}}}:
{{{(y-2)/(4-2)=(x-1)/(3-1)}}} and then rearrange to give y in terms of x:
{{{(y-2)/2=(x-1)/2}}}
{{{y=x+1}}}
so comparing with "y=mx+b", m=1 and b=1.

I hope this helps,
Adam.
P.S. please check out my website, it may be helpful to you:
http://www.geocities.com/quibowibbler