Question 450034
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Let *[tex \Large m] represent the amount charged per mile.  Let *[tex \Large d] represent the daily fee.


In the first situation, where the mileage fee represents the cost of traveling 300 miles, that cost can be expressed as *[tex \Large 300m].  That is, the number of miles traveled times the cost per mile.  Furthermore, the cost for the daily fee for the 3 days is represented by *[tex \Large 3d], i.e. the number of days times the daily fee.  The sum of the two is given as $69, hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 300m\ +\ 3d\ =\ 69]


In a similar fashion, we can derive another equation that describes the second situation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 600m + 5d\ =\ 123]


Now all you have to do is solve the system for the ordered pair *[tex \Large (m,d)].  Hint:  Since the larger coefficient on *[tex \Large m] is an integer multiple of the other, this system lends itself nicely to the Elimination method.  Just multiply the first equation by -2 and proceed.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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