<PRE><B>Question 450006</B>
Determine the largest angle in any triangle ABC with sides a=7, b=18 and angle A= 20 degrees

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sin(B)/18 = sin(20)/7
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sin(B) = 18[sin(20)/7]
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sin(B) = 0.8795
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B = sin^-1(0.8795) = 61.58 degrees.
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So C = 180-(20+61.58) = 98.42 degrees (largest angle)
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Cheers,
Stan H.</PRE>