Question 449922
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
Find the z-scores for which 98% of the distribution's area lies between -z and z.  
That is: .01 < P < .99  NORMSINV(0.01) = -2.33  AND NORMSINV(0.99) = 2.33
 See below: distribution area is between the short vertical green lines.
short vertical lines plotted at z = -2.33 and z = 2.33
{{{drawing(400,200,-5,5,-.5,1.5, graph(400,200,-5,5,-.5,1.5,0, exp(-x^2/2)), green(line(-2.33,0,-2.33,exp(-2.33^2/2)),line(2.33,0,2.33,exp(-2.33^2/2))),locate(4.8,-.01,z),locate(4.8,.2,z))}}}