Question 46764
Let x be the first odd integer, x+2 the next consecutive odd integer, and x+4 the third consecutive odd integer.  From the problem description, you can write:

x + (x+4) = 5(x+2)-63 Simplify and solve for x.
2x+4 = 5x+10-63
2x+4 = 5x-53 Subtract 2x from both sides of the equation.
4 = 3x-53 Add 53 to both sides.
3x = 57 Divide both sides by 3.
x = 19
x+2 = 21
x+4 = 23