Question 449482
An airplane takes five hours to travel a distance of 3600 km against the wind. The return trip takes four hours with the wind. What is the rate of the plane in still air, and what is the rate of the wind?
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3600/5 = 720 mph
3600/4 = 900 mph
The airspeed is the average = (720+900)/2 = 810 mph
The windspeed is the difference = 900-810 = 90 mph