Question 449462
The equation is:
6x^2-1=2x 

Now using the formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


Here,
a=6
b=-2
c=-1

For these solutions to exist, the discriminant  should not be a negative number.

First, we need to compute the discriminant : d=b^2-4a*c...
Solving we get d=28

Discriminant d=28 is greater than zero. That means that there are two solutions:

The formula is:
 {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
By substituting the values of a,b,c in the above equation we get the answers as:

x=0.207625
x=-0.274291