Question 449457
(2x-1)(x+2)=9


(2x(x+2)-1(x+2))=9
2x^2+4x-x-2=9
x^2+3x-11=0

Find the roots of the equation by quadratic formula							
							
a=1,b=3,c=-11
							
b^2-4ac=9+44				
b^2-4ac=53
sqrt(53)=7.28
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(-3+	7.28)/	2		
x1=2.14						
x2=(-3-7.28) /	2			
x2= -5.14