Question 449466
{{{(1/2x^2)-(1/2x)-(15/32)=0}}}

LCD = {{{32x^2}}}

{{{16 -16x-15x^2=0}}}

Rewrite
{{{15x^2+16x-16=0}}}

Find the roots of the equation by quadratic formula							
							
a=	15,	b=	16,	c=	-16,		
							
b^2-4ac=256+960				
b^2-4ac=1216			
sqrt(1216)=34.87
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(-16+34.87)/	30		
x1=	0.63						
x2=(-16	-34.87)/30			
x2= -1.7