<PRE><B>Question 449358</B>
On monday roger drove to work in 16 minutes.
 Tuesday he averaged 11mph more and it took him 4 minutes less.
 How far does he travel to work?
how would you set this problem up? 
:
Let s = his speed on Monday
then
(s+11) = his speed on Tuesday and it takes him 16-4 = 12 min
:
Times have to be in hrs
:
Write a distance equation, dist = speed * time
:
Mon dist = Tues dist
s * {{{16/60}}} = (s+11) * {{{12/60}}}
multiply both sides by 60
16s = 12(s+11)
16s = 12s + 132
16s - 12s = 132
4s = 132
s = {{{132/4}}}
s = 33 mph on monday
then
33 + 11 = 44 mph on Tues
:
Find the dist
33 * {{{16/60}}} = 8.8 miles
:
Check it on Tuesday, should be the same
44 * {{{12/60}}} = 8.8 mi</PRE>