Question 449247
First set the equation to zero:{{{3y^2+14y-5=0}}}, solve the equation by factoring

{{{3(3y-1)(3y+15)=0}}}.Set each factor to zero: 3y-1=0=> y=1/3 and 3y+15=0=>

y=-5. The roots are:{ -5, 1/3 }.