Question 449150
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
y=x(x+2)   |Putting into vertex form
y=x^2 + 2x  |Completing the square
y = (x+1)^2 - 1  |Vertex is (-1,-1) and  Line of symmetry is x = -1

{{{drawing(300,300,   -6, 6, -6, 6,  blue(line(-1,6,-1,-6))  , grid(1),
circle(-1, -1,0.3),
graph( 300, 300, -6, 6, -6, 6,0,(x+1)^2 - 1 ))}}}