Question 46660
{{{h = -16t^2 - 32t + 320}}}
{{{64 = -16t^2 - 32t + 320}}}
{{{0 = -16t^2 - 32t + 256}}}
{{{0 = t^2 + 2t - 16}}}
{{{x = (-b +- sqrt( b^2 - 4*a*c ))/(2*a) }}}
{{{x = (-2 +- sqrt( 4 + 64 ))/(2) }}}
{{{x = -1 +- sqrt( 17 ) }}}