Question 46551
R = k*l *(1/(d^2))
R = resistance of wire
k = proportionality constant
l = length of wire
d = diameter of wire
{{{36 = k*2000*(1/(.6)^2)}}} all values in cm.
{{{36 = k*2000/.36}}}
{{{k = 36*.36/2000}}}
{{{k = 1296/(2*10^5)}}}
{{{k = 648*10^(-5)}}}
{{{R = k*l *(1/(d^2))}}}
{{{R = k*6000*(1/(1.2)^2)}}}
{{{R = 648*10^(-5)*6*10^3*(1/1.44)}}}
{{{R = 6*648*10^(-2)*.6944}}}
{{{R = 2700*10^(-2)}}}
{{{R = 27}}}
27 ohms is my answer, too
a quick check
The 2nd wire is 3 times as long and 4 times the 
cross-section area of the 1st wire
R2 = 3/4*R1
R2 = (3/4)* 36
R2 = 3*9
R2 = 27 ohms
OK