Question 448746
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1.  Pick a value for *[tex \Large x], it can be anything you like, but I would choose a small integer divisible by 3.  Note: Either -3, 0, or 3 would do nicely.


2.  Substitute the chosen value in place of *[tex \Large x], then do the arithmetic to determine the resulting value of *[tex \Large y].


3.  Form an ordered pair *[tex \Large (x,\,y)] where the *[tex \Large x] value is the value you chose in step 1 and the *[tex \Large y] value is the value you calculated in step 2.


Repeat the process 2 more times chosing a different value for *[tex \Large x] in step 1 each time.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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