Question 448575
Suppose 1.5 percent of the antennas on new Nokia cell phones are defective. 
For a random sample of 200 antennas, find the probability that:
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Binomial Problem: n = 200 ; p = 0.015 (defective) ; q = 0.895 (not defective) 
1. None of the antennas is defective.
P(200 not defective) = 0.895^200 = 2.315.10^-10
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2. Three or more of the antennas are defective
P(3<= x <=200) 
= 1 - P(0<= x <= 2) 
= 1 - binomcdf(200,0.015,2) 
= 0.5785
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Cheers,
Stan H