Question 448581


{{{abs(a+bi)=sqrt(a^2+b^2)}}} Start with the absolute value of a complex number formula. This is also known as the magnitude of a complex number formula.



{{{abs(4+7i)=sqrt((4)^2+(7)^2)}}} Plug in {{{a=4}}} and {{{b=7}}}.



{{{abs(4+7i)=sqrt(16+(7)^2)}}} Square {{{4}}} to get {{{16}}}



{{{abs(4+7i)=sqrt(16+49)}}} Square {{{7}}} to get {{{49}}}



{{{abs(4+7i)=sqrt(65)}}} Add



{{{abs(4+7i)=8.06225774829855}}} Take the square root (this figure is most likely approximate)



So the solution is approximately {{{abs(4+7i)=8.06225774829855}}}