Question 448546
<pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
rational roots of the equation 
 x^3-4x^2-4x+16=0   |If x = 2  then 8-16-8+16= 0
 x^3-4x^2-4x+16)/(x-2) = x^2-3x-10
 (x-2)(x^2-2x-8) = 0
factoring further
 (x-2)(x-4)(x+2) = 0   Rational roots: 2,4,-2
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circle(2, 0,0.3),
circle(4, 0,0.3),
circle(-2, 0,0.3),
graph( 300, 300, -6, 6, -6, 6,0,x^3-4x^2-4x+16))}}}