Question 448544
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Hi
 Standard Form of an Equation of an Ellipse is {{{(x-h)^2/a^2 + (y-k)^2/b^2 = 1 }}}where Pt(h,k) is the center 
and a and b  are the respective vertices distances from center.
x^2+4y^2+12x-32y+96=0 
 (x+6)^2 - 36  + 4(y-4)^2 - 4*16  + 96  = 0   
 (x+6)^2 + 4(y-4)^2  = 4
{{{ (x+6)^2/4 + (y-4)^2/1  = 1 }}}  Center (-6,4)