Question 448174
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Hi
Standard Form of an Equation of a Circle is {{{(x-h)^2 + (y-k)^2 = r^2}}}
where Pt(h,k) is the center and r is the radius
x^2+y^2-7x+6y+1=0
 (x-3.5)^2 - 12.25 + (y+3)^2 -9 + 1 = 0
 (x-3.5)^2  + (y+3)^2  = 20.25