<PRE><B>Question 448361</B>
&lt;pre&gt;&lt;font face = &quot;consolas&quot; color = &quot;indigo&quot; size = 4&gt;&lt;b&gt;
4th term of (4x+y)&lt;sup&gt;6&lt;/sup&gt;

The formula for the kth term of 

(A + B)&lt;sup&gt;N&lt;/sup&gt;  is

C(N,k-1)A&lt;sup&gt;N-k+1&lt;/sup&gt;B&lt;sup&gt;k-1&lt;/sup&gt;

So substitute A = 4x, B = y, k = 4, N = 6

C(6,4-1)(4x)&lt;sup&gt;6-4+1&lt;/sup&gt;y&lt;sup&gt;4-1&lt;/sup&gt;

C(6,3)(4x)łył

20(4x)łył

20*4łxłył

20*64xłył

1280xłył

Edwin&lt;/pre&gt;</PRE>